The vast majority of golfers will go their entire life without recording a hole-in-one, and the vast majority of people who are able to check an ace off their bucket list will do it on a par 3. Achieving it on a par 4 is an incredibly rare feat, but one golfer was able to do exactly that on two consecutive holes in that particular category.
Based on the odds compiled by the PGA of America, the average golfer has a 1-in-12,500 chance of making a hole-in-one at some point during their playing days.
That pales in comparison to the chances of making an albatross (three strokes under par on a single hole), as the probability of getting an ace off the tee on a par 4 or holing out on your second shot on a par 5 rises to 1 in 6,000,000.
According to Golf Digest, Iowa City resident Jack Wiebe may have pulled off one of the wildest feats in the history of golf thanks to what transpired during a recent round where he tallied his first albatross of the day after hitting a blind shot on a par 4 only to discover his ball had ended up in the hole on the 9th when he made his way down to the green just before hitting the turn.
Wiebe—who was a member of the golf team at the University of Iowa and previously had 14 aces under his belt )—was planning on laying up when he stepped up to the tee box on the 11th hole, which was the next par 4 on the course.
However, his playing partner convinced him to pull out his driver, which turned out to be a very smart choice when you consider he was able to drive the green before the ball ended up at the bottom of the hole yet again for his second albatross of the day.
After a quick search, I can’t find any evidence that suggests there are any other golfers who’ve achieved what Wiebe was able to do, which makes sense when you consider the theoretical odds of doing what he did are 1 in 36 trillion.
Must be nice.
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